The Tower of Eternity 1F

[Master Yo]

Adheisive where?

Where is the adheisive?

[Airtamis]

Hmmm I found a green key, a Memos 1 and 2, and an adhesives (used)..

[Emjay]

Can I refer you back to Uncle Rim's post above? There really is no hidden trickery, counting pen strokes, casting runes, reading entrails...

There are 3 sets of codes:

The 10 digits on the wall correspond to the lower-case lettters "a" through "j".
The 10 digits on the memo 2 correspond to the upper-case lettters "A" through "J".
The 10 digits on the memo 3 correspond to the numerals "0" through "9".

So:

c+i+j (from the wall) is 1+2+2 = 5
A+H (from memo 2) is 3+3 = 6
4+5 (from memo 3) is 2+2 = 4
f+D+9 (from all three) is 2+2+1 = 5

(P.S. I'm from planet Earth, if that helps. Most people here have around 10 fingers, hence the above solution -- though evidence suggests that older computer programmers tend to have 16 fingers )

[Emjay]

OK -- one more attempt to explain it...

How can I unhook you from this fixation that it's asking for the 4th and 5th digit from the list? 'Cos it isn't. You managed to make the conversion when the codes were lettters (the wall and memo 2). When it said use code "c", you didn't try and count the c'th digit from the list (whatever that is. 12 maybe?) You looked for the letter "c" in the codes, and found the digit in the same place. The codes ran "a", "b", "c", "d"... and the corresponding digits ran "1", "1", "1", "1"...

Now do the same for memo 3. Forget that the codes are numbers. They're just pretty shapes that look like this: "0", "1", "2", "3", "4", "5", "6"..., and they correspond to the digits "1", "1", "1", "1", "2", "2"...

This is how they line up:

Code
0 1 2 3 4 5 6 7 8 9
^ ^ ^ ^ ^ ^ ^ ^ ^ ^
| | | | | | | | | |
v v v v v v v v v v
1 1 1 1 2 2 1 1 1 1
Digit

Which digit lies opposite the code that looks like a triangle with two extra-long sides ("4")? It's a 2. Which digit lies opposite the code that looks like an upside-down swan ("5")? It's another 2. Add the two 2s together and you get...?

I'm not counting over anything. I'm just matching patterns in a standard substitution cipher, samer as I did for the wall and memo 2.

As a similar exercise, try this one. What colours are the following words?

red blue green black

(blue, orange, purple, green)

Right -- I'm off to do floor 45 which has just appeared.

[Emjay]

Because, actually, that IS what I DID do, LOL ... counted over to the C

Ah -- no, you didn't COUNT over to "c". That would have been "0 1 2 3 4 5 6 7 8 9 a b c", and you would have run off the end of the list before you reached "c". What you did was...

...just recited the alphabet while counting over each number.

Now do EXACTLY the same using a series of numbers instead of letters. Start reciting "Zero", "One", "Two", "Three", "Four" while counting over each number (first one, second one, third one, fourth one, fifth one). When you recited "Four", what number had you counted up to? (Clue: it's more than 4 but less than 6.)

And if you still don't see it, try this:

Suppose the clue had said not "4+5", but had said "0+5". What would the answer have been? There is no 0'th number in the list, so there is no way you could just count up to it.