Originally posted by tallerbird
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Web-Hopper Riddle
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Originally posted by A935Got 93? Does that mean you have the answer or have deduced there are 93 numbers to try?
Finally solved it and got the answer, even once you crack the code the answer isn't that easy to come by. However the next one absolutely makes me want to quit this game.
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Originally posted by StratFinally solved it and got the answer, even once you crack the code the answer isn't that easy to come by. However the next one absolutely makes me want to quit this game.
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Yes, I will:
each row of numbers in the backround have 14 digits that repeat and are unique to that line. Each letter in the gibberish corresponds consecutively with the rows of digits. You can only use the first 14 going left to right.
map out the letters in blocks of 14, continuing down the rows with each set of 14 letters and 14 numbers. You need another map of each letter of the alphabet and it's corresponding number, a=1, etc. so the first letter Y is 2 left of it's actual position because y and 2 are the first characters. The second letter in the gibberish is going to correspond the same way, however many characters left of the original position of the letter in the map.
If that doesn't make sense, here is the gist of the code. Don't read it if you don't want to know.
what is the largest number when multiplied by itself that gives you a nine digit number with all unique numbers (pandigital)
Took me most of the day off and on to map that and now I'm stuck again!
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How about a tip on this one? I think I overworked my brain on the last one:
BBCBCCDBEFCDBEDBBFEEFFCDFFFFDEEDDEBDBEDDDCFCBDEBDE EBECDC
CDECBFCCDCDBDFBDBBCFCDBBCCEFFEDDBBDDDCBEEFFBDDEECC CCDBEB
FCAAAAAAFEEEAAAAADDBCAAAAFAFAAAEFFAAAFEDAAACECEAAA AAADBD
CECAEBBCAFEEEEAEEFDDACFBFAADCADDEEDAEDBAFEFADCFEAD ECCAFB
FEBAFEEFADCECCAEFFCDAFDCFBABCABEFCBAFCACBDFFACEFAE BDFAFE
EDFAFBCEABECBCACDBFBABCDDCDBCADBDDBABDAFBCBEADBBAB CBCACB
EBFAAAAABCFFEEAFECFDEAAADECDCAAAAAAAFBABDFBCABFDAD BECACF
BDCAEDDBAEFEFFACDCBCEEDFAAFBBADEDBCAFFABFCCDAFDCAA AAAEFF
EBDADEFCADFEEBAEECFDBFEFEBAEFABBBEDACDABDBCCACEBAC FEBFDC
DFBADFCFAECBBCAFBDFFAFDEEFABDACFDFDADBADCEECADDCAB FEFFFD
BFBAECCFABDDEDACCDFCAAEDEDACBAEDFCCABCFAFFFAFCDEAD CBFFCB
CBAAAAAAEBFEAAAAACEBADAAAAEFAAACFCAAAEEBAAAEDFCAAA AEFCEC
DDFECDDEBEFDCBCBDBFCCEDCBDBBBECEDBCFCDBFFEFCCCDFCF FFFBFC
FBCFFBDEECBEFECEDDEFBFDBECEDFCDBEDDCFBCDDEFECBCBCD DBBFDB
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Originally posted by StratYes, I will:
each row of numbers in the backround have 14 digits that repeat and are unique to that line. Each letter in the gibberish corresponds consecutively with the rows of digits. You can only use the first 14 going left to right.
map out the letters in blocks of 14, continuing down the rows with each set of 14 letters and 14 numbers. You need another map of each letter of the alphabet and it's corresponding number, a=1, etc. so the first letter Y is 2 left of it's actual position because y and 2 are the first characters. The second letter in the gibberish is going to correspond the same way, however many characters left of the original position of the letter in the map.
If that doesn't make sense, here is the gist of the code. Don't read it if you don't want to know.
what is the largest number when multiplied by itself that gives you a nine digit number with all unique numbers (pandigital)
Took me most of the day off and on to map that and now I'm stuck again!
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