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I love that kind of problems!!! Just give me a couple of minutes for TRYING to solve it...
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Going on a trip around the universe on a convertible
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Gotta Go Chat with ya later - byeLife is not a problem to be solved, but a mystery to be lived"The best way to cheer yourself up is to try to cheer somebody else up."Comment
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Hey Adventure
Bye Darknight...Going on a trip around the universe on a convertible
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I remember when I learnt how to solve this...But I don't remember how!!!Originally posted by Samuelgotta prove they are equal, dont know how though
Going on a trip around the universe on a convertible
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Oh, well if nobody else finds it out, I got itOriginally posted by Samuelgotta prove they are equal, dont know how though
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Oh no I hate this kind of math. Sorry I pass, but how important is it to solve? Hope Mystery got any success. Go Girl!Originally posted by Samuelok well give this a try
(1+a/b)/(1-a/b) = (b+a)/(b-a)
@Darknight
Good night. See you later!
Faily of Kzin
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Hii, Doglover! Good ta see ya!!
@Darknight
Oh, nooo...oh, well, see ya Darknight!
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lol wanna be my math teacher for the day?Originally posted by MisteryOh, well if nobody else finds it out, I got it
I made a riddle! Try it here
i have but one request, DONT CALL ME SAMUEL, lets see you try to figure that out!Comment
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Uhm... Mistery, you do know you have that REVENGE thing to think of....Comment
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I like algebra and equations (is algebra and equations the same?)... But I can't really remember how this one...I had some problems with it when I was learning it...Originally posted by Adventure lol
@Lilli, good to see you too!Going on a trip around the universe on a convertible
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i learned this in class but not how to do it with fractions upon a fraction
I made a riddle! Try it here
i have but one request, DONT CALL ME SAMUEL, lets see you try to figure that out!Comment
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I learnt something like this, but I don't remember the rest!!! I learnt this when I was about (maybe a month before) to end my school year...Originally posted by Samueli learned this in class but not how to do it with fractions upon a fraction
Attached FilesGoing on a trip around the universe on a convertible
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It is not that easy on the forums, because it is hard to write algebra on it
But well, first you have to multiply by both denominators, so you get
(b-a) x (1+a/b) = (b+a) x (1-a/b)
then solve the equations:
b+ab/b-a-a^2/b = b-ab/b+a-a^2/b
next step is to reduce the fractions (e.g. ab/b=a)
So you get:
b+a-a-a^2/b = b-a+a-a^2/b
Or shorter:
b-a^2/b=b-a^2/b
Hope it's more or less clear (and I didn't make a typo), otherwise ask.Comment
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You mean The RIDDLER!!!! vs. Mistery - Part 2?Originally posted by Lilliputt
Yes, this will follow soon
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Originally posted by MisteryYou mean The RIDDLER!!!! vs. Mistery - Part 2?
Yes, this will follow soon
HURRAH!!!!!
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