Uncharm 12 Rupertcauns

[ThemePark]

jack, how did you work out the solutions to those mazes? Did you just try and try again, or did you use some kind of pattern?

Edit: btw, I love your avatar.

[ShiningStar]

Think of the numbers like the ones on an odometer. When they can't go any higher they roll over again to the beginning. (don't forget to adjust the other digit acordingly)

ok well doing that I get

81 and 11 which doesn't work, i'm doing something wrong

[jack]

@themepark

Honestly it was more trial and error more than anything else. If one of my attempts looked more promising than the others I would try to figure out if there was a way to make it work, but other than that I really didn't have a system.

@shining

try

81 and 12

[ShiningStar]

1 digit again lol Thanks Jack!!

[Tobble]

Finally completed them all....thanks for hints

[ThemePark]

I solved the second maze, but I'm now stuck on the third maze, where I managed to cover all the squares except one. And this is the last room I have left. So if anybody have any ideas about the path, I'd really appreciate it.

[ATTACH]7257[/ATTACH]

[jack]

I have been working that one in paint for a little bit and haven't had much luck so far.

[Adventure]

I solved the second maze, but I'm now stuck on the third maze, where I managed to cover all the squares except one. And this is the last room I have left. So if anybody have any ideas about the path, I'd really appreciate it.

[ATTACH]7257[/ATTACH]

Found it:

[ThemePark]

Leontien, you are nothing short of brilliant!

So here are the 3 solutions:

[ATTACH]7262[/ATTACH]

[KAM]

Ok - I must be missing something...how are we to see the whole sudoku board?

nvm- posting power....

[~*Mercedes*~]

I finished t his game today..and I am darn proud..that was a hard time consuming game...if u finish this..pat yourself on the back..lol..and those mazes...argggg...

As for the numbers..depending one which room u are in..there are two rooms with equations..

The first room is taking the constant number and minusing one..so if ur numbers are..

2 10 11 21

2+10-1 = 11
10+11-1= 21
11+21-1= 31
21+31-1= 51

You reverse them, so if your numbers are 55 52 22 19 it would be

55-52 =3
25-3 =22
22-3 =19
91-3 =88 and so fourth..i hope that helps..

[leapfrog]

Chess Queens

Does anyone have a second solution for this?
I have the first solution from the website in previous posts... now stuck on the second board.

[~*Mercedes*~]

Does anyone have a second solution for this?
I have the first solution from the website in previous posts... now stuck on the second board.

i belive this one solves both of them for you

http://www.math.utah.edu/~alfeld/queens/queens.html

[leapfrog]

Hey thanks but I solved it because I didn't understand the website! Haha...

Now I have only 4 levels to go... it's getting too hard for me

[~*Mercedes*~]

Hey thanks but I solved it because I didn't understand the website! Haha...

Now I have only 4 levels to go... it's getting too hard for me

It is very hard..and it takes up time...it took most days to complete it..so don't feel bad..it was for everyone..and anyone who says it isnt is just sad..lol..

by the way..if u would have waited for it to load u would have seen a picture..but it took a while for it to load..lol