Chit-Chat

[EscapeGirl]

Hey Freakshow! I see your avatar and "aspiring author" has returned. Nice! Like the image thing in your sig, too.

[Adventure]

Yeah Freakshow. You have your old style back! Thank God!

[ThemePark]

Freakshow, there are at least one book that I recall having heard of that's translated to English and avoids the use of E in the entire book. Perhaps that would be a good inspiration for you for this game

[Freakshow59]

I want that new part of my sig to be visible, problem is I can't make it. . .

[Mistery]

Freakshow, it is not possible to post pics in the signatures except from smilies.

[Adventure]

@All
Oh yes, we now have 50 characters more for our signatures. Just thought you like you know. But I hope I will get 50 more. Waiting still for answer..

[doglover]

I'm back.
This is the PM that Hollandgirl sent me:

Both sides have that thing above (dunno the word in english, literally translated from dutch it means carrot ) , so you if you gotta square (i just found it in our dictionary, i mean the two above the numbers.. christ i wish i could be more english) them both. after that, this is what you have:

202 + x2 = 102 + (10 + x)2

So after that you gotta work out the (10 + x)2
That means: (10 + x) x (10 + x) (x between the two () means 'multiplied by')
So now you've got:

202 + x2 = 102 + 100 + 20x + x2

After that work out the squared numbers, so you've got:

400 + x2 = 100 + 100 + 20x + x2

After this get all the numbers in front of the '='

x2 - x2 + 400 - 100 - 100 - 20x = 0

Work this out, now you've got:

200 - 20x = 0

Get the 200 on the other side of the '='

-20x = -200
x = -200/-20
x = -10

I hope it's correct! I might have used a total wrong method...

Hollandgirl

But...
When I was solving the problem, I just saw a little detail...
Right on the beggining we have a square root, though, all the numbers are 'squared' (lol), so, the square root and the squares eliminate themselves, isn't it?

[Freakshow59]

awh. .. that sucks. . .

ttly diffy note, I need help, here's the problem: Find the value of the variable: 4= 2/9(4y-2)

I'm only smart when I'm bored, guess what? I'm not

[ThemePark]

Only when the equation under the square root only consists of multiplying or dividing numbers. As in this case they don't eliminate eachother because there are additions instead.

Further more, in order to remove the square roots on the left for instance, you'd have to multiply both sides with the square root of (20^2 + x^2). On the left that way you'd remove the square root, but on the right you'd just be multiplying with a new square root, so it wouldn't help, that's why I'm stuck

Freakshow I'm gonna PM you how to solve that one.

[Adventure]

Hmmm Root madness..

[Freakshow59]

its not roots, its solving mutlistep equations, that problem involves recipricles. . . or something like that. . .

[doglover]

@ThemePark
Okay, I'm sorry but I have to say this... I'm even more confused than before!!!

[ThemePark]

its not roots, its solving mutlistep equations, that problem involves recipricles. . . or something like that. . .

Now I'M confused! I don't like math in English

doglover, sorry I will PM you about this and try to make it more clear.

[Mistery]

Freakshow, could you solve your equation?


Haha, you should hear my hubby: "The loony gang trying to solve multiple equations with square roots?!? "

Umm....

[doglover]

@Mystery, ROFL!!! Your hubby is really funny!!!

Oh, and I just checked the solution of the problem (x=10), so, I guess that the equation I created is correct...the only problem is solving it!